Login
Sign Up
Home
Program
Project
My Zone
Support
Show Code
Browse Program
Search Program
Sum Of Consecutive Squares
Input Variables
Output Variables
Program Code
Description
Variable Name *
(dynamic type)
UP
Down
Delete
Default Value *
Description *
Multi Lines
Variable Name *
(dynamic type)
UP
Down
Delete
Description *
Input Variables List
Output Variables List
Source Code
sum=( ( n * ( n + 1 ) * ( 2*n + 1 ) ) / 6.0);
Subject
Description
This online calculator is used to calculate the sum of consecutive squares. The sum of the squares of any number of consecutive integers starting with 1 is the square of some integer.
Formula:
Sum of consecutive squares = ( ( n * ( n + 1 ) * ( 2n + 1 ) ) / 6)
Category
General
Created By
tech
Created Date
11/28/2010
Last Modify Date
9/7/2011
Calculation Count
19
Version
1.00
Positive
0
Neutral
0
Negative
0
Related Program ID
34 , 35 , 36 , 38 , 39
Copyright ©2009-2010 CUI WEI. All Rights Reserved.